Answer Choices
mode < median < mean
mode < mean < median
median < mode < mean
mean < mode < median
Explanation for Question 17 From the Math (Calc) Section on the Official Sat Practice Test 8
So question 17 gives us a data table about the ages of 20 students 2 enrolled in a college class. And they're asking us for what is the mean, 3 the median and the mode in order. And so in order to do this 4 problem, we need to remember what these three things mean. 5 And so the first one, the easiest one perhaps to do is mode. 6 So we'll think about mode first and mode just means the most common, 7 the data value that shows up the most number of times. 8 And for that, we need to look at the frequency because frequency also means 9 how often something showed up. So the mode is going to have the highest 10 frequency. We see that the highest frequency is six, 11 right? So our mode is going to be 18. 12 So our mode is actually the lowest possible value that we can have here. 13 So it's pretty, um, probable that we'll have either a or B here, 14 um, because the mode is the lowest possible age, 15 right? 16 And so then we can think about the median. Now, 17 if we have a class of 20 students, 18 we know that our median is going to be in between the 10th and 19 11th value because the half of 20 20 is 10, right? But if we have an even number of data values, 21 we're going to have to split it directly in half. And so it's going 22 to be between the 10th and 11th data value. So now the sixth value 23 is 18. And then here are the 11th value would be 19, 24 right? We know it's the 11th value because six plus five 25 is 11. So if we were to write all of these data values out 26 in a list, ...