Explanation for Question 33 From the Math (Calc) Section on the Official Sat Practice Test 3
Now, here are number 33. We are given an expression or we're told that 2 ABC or constants, and we want to know the value of B. 3 And so in order to do that, we have to start by distributing out 4 this negative two so that we can get rid of the parentheses. 5 Right? So we'll begin by writing the expression as normal. 6 Now, negative two times X squared is negative two X squared, 7 negative two times, negative two X. 8 It's going to be positive for X and negative two times negative one. 9 That's positive two. So now we can combine like terms, 10 right? We've got three negative, three X squared, 11 minus two X squared gives us negative five X squared. 12 We've got plus five X plus four X. 13 Um, and that is going to be plus nine X. 14 Right? And then finally, 15 we've got minus two plus two, 16 and that is going to give us, um, 17 zero. And so now that we've distributed all of that out and we're looking 18 for what B is. We see that B's what is attached in front of 19 the X, which in this case is a nine. 20 So then our answer here is going to be that B is equal to 21 nine.