Explanation for Question 36 From the Math (Calc) Section on the 2019 May Sat
So number 36 says in the equation above the kinetic energy, 2 K of a 200 gram object is given in terms of its speed. 3 V. If the equation is rewritten in the form V equals a root K, 4 where a is a positive, constant, 5 what is the value of a? So all we need to do here is 6 take our original equation, which is up here K equals 200 V 7 squared over two, and plug in a root K for V 8 into that equation. So let's do that. 9 Let me rewrite. This first K is equal to 200, 10 a root K squared over 11 two. Now this can be written as K is equal 12 to a hundred, a K squared. 13 And that's just because I simplified it by dividing 200 by two next 14 I'm going to square a K and I'm going to get a 15 squared. Okay. I can divide both sides 16 by K and that gives me one is equal to a hundred, 17 a squared then divide both sides by 101 18 over 100 is equal to a squared. 19 And finally I can route both sides to get route one over 100 20 is equal to a, or that can be written as one over 21 10 in its simplified form. And that is the correct answer to this question.