Explanation for Question 4 From the Math (No Calc) Section on the 2019 March Sat
Question four says, what is the solution to negative three times X minus 2 five is equal to negative two X plus four. 3 So to solve this problem, we're going to need to distribute the left side 4 of the equation, add and subtract like terms and then solve for X. 5 So let's start by distributing. So the left side of the equation becomes negative 6 three X plus 15, 7 and that's equal to negative two X plus four. 8 Now I'm going to add three X to both sides of the equation, 9 and I'm going to subtract four from both sides of the equation. 10 And that's going to give me 11 is equal to apps. 11 And so our answer is a 11.