[Video] Q20: (x-6)^2 + (y-3)^2 = 25the graph in the xy-plane of the equation above is a circle. if the circle is translated downward a units such that the circle is tangent to the x-axis, the equation becomes (x-6)^2 + (y-3+a)^2 = 25. what is the value of a?

Explanation for Question 20 From the Math (No Calc) Section on the 2019 April Sat

In number 20, we are given the equation for the graph of 2 a circle. We want to know if the circle is translating downward, 3 a unit such that the circle is tangent to the X axis. 4 What is the value of a, that makes the equation X minus X squared, 5 plus Y minus three, plus a squared is equal to 25. 6 So this is a little bit confusing to think about mentally. 7 So I'm going to make a picture. 8 So we start off with the circle that has this equation. 9 So I'm going to use that equation to find the center and the radius 10 of the circle. If you know the general equation of a circle, 11 that would be very helpful. And that is X minus 12 H squared. Plus Y minus K squared is 13 equal to R squared. This one is a very good one to memorize if 14 you haven't already. 15 So using this equation, the center happens at the point HK 16 and the radius is equal to R so you have to remember to take 17 the square root of R squared. 18 So now, if I look at this equation, 19 the center is at the 0.63. 20 Remember to take the opposite sign that that's what's inside because the original 21 equation has a minus side. And then the radius is 22 equal to five. 23 Since the square root of 25 is equal to five. 24 So now that I have that I can drop my first picture of this 25 circle, six three would be about here. 26 And then that means a circle would look something like 27 this. It just has to be a rough sketch. Nothing that'll take too much 28 time. So now we want to translate the circle, 29 downward ...

All Test Answers +

Online SAT Prep Tutoring

1-on-1 SAT and ACT tutoring with an expert SoFlo Tutor via Zoom

BOOST MY SCORE