Explanation for Question 14 From the Math (No Calc) Section on the Official Sat Practice Test 9
Okay. Question 14 gives us these two expressions and it asks in 2 which of the following does the shaded region represent the solution set and the 3 X, Y plane to the system of inequalities above. 4 So we're trying to find out essentially when you graph these two lines, 5 so this being line one and this being linked to where do 6 they intersect? And then where can you shade in to make this system of 7 inequalities? True? What region of the graph fulfills both sets of inequalities? 8 So my preferred method for this one is let's pick a random point. 9 And for our purposes, zero, zero is a pretty good one. 10 And we can see that zero is zero is only included in one of 11 the regions. So if is zero fulfills, 12 both of these inequalities, we can pick a is our best choice. 13 So going through, if we plug in zero, zero, 14 we get zero is greater than or equal to zero 15 plus two. 16 So this is not correct. Zero is not greater than or equal to two, 17 so we can cross out a, as an answer choice. So now let's choose 18 another point. Let's choose the 0.04. 19 Now, if this one's cracked C will be our answer choice. 20 So we plug in four is greater than or equal to zero plus two. 21 That is true. Let's also plug in the point to two X plus 22 three, Y is less than or equal to six. 23 So we have two times zero plus three 24 times four is less than or equal to six. 25 That gets us to 12 is less than or equal to six. 26 And that's not correct. So we can cross out C moving on. 27 Let's pick ...