[Video] Q19: If 3p − 2 ≥ 1, what is the least possible value of 3p + 2?

Explanation for Question 19 From the Math (Calc) Section on the Official Sat Practice Test 4

So here in number 19, we're told that three P minus two is greater 2 than or equal to one, and we need to know the least possible value 3 for three P plus two. Um, 4 and so you might be able to confused about this one cause they want 5 you to solve for three P plus two. But what you have here is 6 three P minus two. Um, but the way that I would go about this 7 problem is to solve for the least possible value of P right? 8 The smallest value that I can get a peak and then plug that in 9 so I can get the smallest value of the whole expression, 10 right? So we'll really just start by solving for P we'll do that by 11 adding two to both sides. That way I can get the twos out of 12 the way here and just be left with three P is greater than or 13 equal to three. 14 So now when I solve for P L simply divide by three, 15 uh, those threes will cancel leaving me with three or P is greater 16 than or equal to one. So now the question is what is the smallest 17 number that P can possibly be, right? 18 And so P can be one or something greater, 19 right? So 1, 2, 3, and anything greater. 20 So the smallest number that P can be is one. 21 So I'm simply going to plug one into this expression here, 22 and then I'll get the smallest number for the entire expression. 23 Right? So three times one plus two is just three plus two, 24 which is five. I'm making my best answer here. 25 Okay.