Explanation for Question 14 From the Math (Calc) Section on the 2019 October Sat
Now number 14 tells us about a fish, 2 a fish hatchery, which has three tanks for holding fish before they are introduced 3 into the wild. So we have 10 fish weighing less than five ounces 4 or in tank a and 11 fish weighing at least five ounces, 5 but no more than 13 ounces are in B 12 fish weighing 6 more than 13 ounces are in. 7 See which of the following could be the median weights of these 33 8 fish. So essentially what's happening here is that we have 10 that weigh less 9 than five, right? So for ones that are less than five, 10 I'll use a, because a is the tank that they're in and we have 11 10 of them. So that's 1, 2, 3, 4, 5, 6, 7, 8, 12 go this way, nine, 10. 13 So now, because I don't know their exact weights, 14 it's just less than five. I put an a to help me kind of 15 solve that issue. 16 And now I also saw that there were 11 that were at least five 17 ounces, but no more than 13 ounces. 18 So I'll call that be right. So I know that B is, 19 um, greater than, 20 or equal to five, but less than 13 ounces, 21 not equal to 13, so greater than, 22 or equal to five, but less than 13. And there's 11 of them. 23 So I'll do 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11. 24 So I have 11 bees now. And then my last one here is going 25 to be C right? Cause tank C has, 26 um, fish that are greater than, or equal to 13 or weighing more than 27 13 ounces. So let me fix this. 28 B is actually can be equal to 13 and it says that see, 29 can weigh no more or weighing more than 13 ounces. 30...