[Video] Q38: The ratio of the population of alaska in 1980 to the population in 1970 can be written as

Explanation for Question 38 From the Math (Calc) Section on the 2019 May Sat

So question 38 says the ratio of the population of Alaska in 1982, 2 the population of Alaska in 1970 can be written as a, 3 to one. What is the value of a, 4 so to find this answer, we're going to need to find both the population 5 of 1970 and the population of 1980. 6 And we're going to need to write it and set it up as equal 7 to the ratio we're giving here. So equal to a 8 over one. Now, 9 if you go over to the graph on the left, 10 you'll see that if you follow 1980 on the X axis, 11 all the way up, it leads you to 402. 12 Now take note. This is actually a typo in the test. 13 It was originally written as four 20, but that number should be 402. 14 So if you originally got the wrong answer, 15 that might be why. So 402 is going to be written as 16 the numerator of our ratio. 17 And that's being compared to the population in 1970, 18 which if we locate 1970 on the x-axis and follow it up, 19 it's 300. So that's, what's going to go on the bottle then 20 to solve this, we can cross multiply. So 300 a is 21 equal to 402, and then a is equal to 22 400 to over 300. 23 And that is equal to 1.34. 24 And that is the corrected.