Explanation for Question 34 From the Math (Calc) Section on the 2019 March Sat
Question 34 says the equation above gets the height of an object above the 2 ground. Y in feet, T seconds, 3 after it is launched from a platform, how many seconds after this launched, 4 does the object reach the ground since Y represents the height in this case, 5 we're going to set Y equal to zero. 6 So we can find when, what the, 7 or how many seconds it will take for the object to be zero feet 8 off the ground. Now, 9 once we do that, we're going to have to factor. 10 So we're going to divide both sides of the equation by negative 16. 11 And then we get T squared plus negative 40 plus 12 negative five. Now this factors into T minus five times 13 T plus one. And so we know that T is 14 equal to five and T is equal to negative one. 15 Now you can't have a negative amount of seconds. 16 Time can't be negative. So the only answer here that makes sense is T 17 is equal to five. And so we know that the answer has to be 18 five.