Explanation for Question 23 From the Math (Calc) Section on the 2019 March Sat
Question 23 says in a right triangle, 2 the tangent of one of the two acute angles is root three over three. 3 What is the tangent of the other acute angle? 4 So I've gone ahead and I've drawn out a right triangle that has two 5 acute angles there, X degrees and Y degrees. 6 We don't know what those values are. Um, 7 and we know that the tangent of one of them is three over three, 8 over three. Now the tangent is the opposite over 9 the adjacent side, the values of the opposite over the adjacent side. 10 So let's say the angle X is the one that has a tangent of 11 root three over three. That would mean that the opposite side. 12 So this one here is route three. 13 And at the adjacent side, this angle, or the side down here is a 14 value of three. Now to find the tangent of the other angle, 15 we have to find the opposite over adjacent values for the other ankle. 16 So all you have to do really is flip this upside down or this 17 original value, and it becomes three over root three. 18 And that's because the opposite, uh, 19 side for angle Y is three and the adjacent side for angle. 20 Why is three? So really you're just flipping it upside down. 21 And the answer here is D.