Explanation for Question 6 From the Math (No Calc) Section on the 2018 April Sat
Question six asks what value of X satisfies the equation above. 2 So I'm going to start by adding two times root X plus one to 3 both sides. So that gives me X plus 28 is 4 equal to two X plus one. 5 Then I'm going to square both sides to get X plus 28 is equal 6 to four times X plus one. 7 And when you factored that out, that becomes X plus 28 is equal to 8 four X plus four. 9 Then I can subtract extra both sides and subtract four from both sides. 10 So if I subtract X, I get, or sorry. 11 If I subtract four, I get 24 on the left side and that's equal 12 to three X. And then finally, 13 when I divide both sides by three, I get X is equal to 14 eight. So the answer is a.